# Leap Year Program in Python using if-else

We will code Leap Year Program in Python using if-else and functions. We will also provide hackerrank solution for leap year program.

In this post, we will make a python program to check whether the given year is a leap year.

Leap Year: One year in every four has 366 days [February has 29 days instead of 28]. The reason why we have leap years is really fascinating, this video does more justice: Video Link

## Algorithm:

If one of the following conditions is satisfied then the given year is a leap year.
• Every year that is divisible by 4 and not divisible by 100.
• A year that is divisible by 4 and also divisible by 400.

## Leap Year Program in Python using if-else

In this program, we will check for leap year using simple if-else conditions. We will take input from the user and typecast it to int and then check whether the given year is a leap year or not using the above algorithm.
```year = int(input("Which year do you want to check? "))

if (year%4==0 and year%100!=0) or (year%4==0 and year%400==0):
print("Leap year.")
else:
print("Not leap year.")

```
Output:

Which year do you want to check? 2022
Not leap year.

Related Posts :

## leap year program in python hackerrank solution

In this program, we will code answers for the leap year question at hackerrank. We completed the is_leap function and it will return true when the given year is a leap year and false otherwise.

```def is_leap(year):
leap = False

# Write your logic here
if (year%4==0 and year%100!=0) or (year%4==0 and year%400==0):
leap=True
return leap

year = int(input())
print(is_leap(year))
```
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1. woowww... what a content
never seen before like this :)
2. Great content
Really works...
1. Thanks 🙏
3. My Code:

year = int(input("Which year do you want to check?"))

if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
print("Leap year.")
else:
print("Not leap year.")
else:
print("Leap year.")
else:
print("Not leap year.")

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