Leap Year Program in Python using if-else

 In this post, we will make a python program to check whether the given year is a leap year.

Leap Year: One year in every four has 366 days [February has 29 days instead of 28]. The reason why we have leap years is really fascinating, this video does more justice: Video Link

Algorithm:

If one of the following conditions is satisfied then the given year is a leap year.

• Every year that is divisible by 4 and not divisible by 100.
• A year that is divisible by 4 and also divisible by 400.
  

Leap Year Program in Python using if-else

In this program, we will check for leap year using simple if-else conditions. We will take input from the user and typecast it to int and then check whether the given year is a leap year or not using the above algorithm.

year = int(input("Which year do you want to check? "))

if (year%4==0 and year%100!=0) or (year%4==0 and year%400==0):
    print("Leap year.")
else:
    print("Not leap year.")

Output:

Which year do you want to check? 2022
Not leap year.

Related Posts :

• Factorial Program in Python
• Python program for palindrome

leap year program in python hackerrank solution

In this program, we will code answers for the leap year question at hackerrank. We completed the is_leap function and it will return true when the given year is a leap year and false otherwise.

def is_leap(year):
  leap = False

  # Write your logic here
  if (year%4==0 and year%100!=0) or (year%4==0 and year%400==0):
      leap=True
  return leap

year = int(input())
print(is_leap(year))

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