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Calculator program in C using Switch Case [New]

In this Calculator program in C, we will perform arithmetic operations between two numbers in c language using switch case and do-while loop.

In this Calculator program in C using a switch case, we will perform arithmetic operations (i.e., addition, subtraction, multiplication, and division) between two numbers in c language using a switch case and do-while loop.

Table of Contents

Calculator program in C using switch case

In this post, we will make a simple calculator using a switch case in c. We can add, subtract, multiply and divide two numbers using this program.
#include <stdio.h>
int main()
{
	int a, b, ch;
	char choice;
	printf("\n Enter two numbers:");
	scanf("%d%d", &a, &b);
	do
	{
		printf("\n Press 1 to add %d and %d", a, b);
		printf("\n Press 2 to subtract %d and %d", a, b);
		printf("\n Press 3 to multiply %d and %d", a, b);
		printf("\n Press 4 to divide %d and %d", a, b);
		printf("\n Enter Your Choice: ");
		scanf("%d", &ch);
		switch (ch)
		{
		case 1:
			printf("Sum: %d", a + b);
			break;
		case 2:
			printf("Subtract :%d", a - b);
			break;
		case 3:
			printf("Multiply :%d", a * b);
			break;
		case 4:
			if (b == 0)
				printf("\n Denominator cannot be zero");
			else
				printf("Divide :%d", a / b); // b should not be zero
			break;
		default:
			printf("Wrong choice!");
		}
		printf("\n Do you want to continue? (Press y/n)");
		scanf(" %c", &choice);
	} while (choice == 'y');
	return 0;
}
Calculator program in C using Switch Case
Output:

Enter two numbers:5 3

Press 1 to add 5 and 3
Press 2 to subtract 5 and 3
Press 3 to multiply 5 and 3
Press 4 to divide 5 and 3
Enter Your Choice: 1
Sum: 8
Do you want to continue? (Press y/n)n

Approach to make a simple calculator program using switch case and do-while loop:-

  1. Initialize three numbers, one number is for the user's choice, and we perform arithmetic operations on the other two numbers.
  2. Input two numbers on which we perform arithmetic operations.
  3. Print all the options and input the preference of the user.
  4. Using the switch keyword, we write all four cases for addition, subtraction, multiplication, and division.
  5. Do not forget to write a break at the end of the case statement.
  6. You can also write a default statement if the user inputs the wrong choice.
  7. for example: - default:printf("Wrong choice!");

Simple Calculator Program in C using functions

In this program, we are making a Calculator program in C using Switch Case and functions.

#include <stdio.h>
int add(int a,int b)
{
    return a+b;
}

int subtract(int a,int b)
{
    return a-b;
}

int multilply(int a,int b)
{
    return a*b;
}

int divide(int a,int b)
{
    return a/b;
}
int main()
{
	int a, b;
	char choice;
	printf("\n Enter two numbers:");
	scanf("%d%d", &a, &b);
	
	
	printf("\n Enter Your Choice (+,-,*,/): ");
	scanf(" %c", &choice);
	switch (choice)
	{
	case '+':
	    
		printf("Sum: %d", add(a,b));
		break;
	case '-':
		printf("Subtract :%d", subtract(a,b));
		break;
	case '*':
		printf("Multiply :%d", multilply(a,b));
		break;
	case '/':
		if (b == 0)
			printf("\n Denominator cannot be zero");
		else
			printf("Divide :%d", divide(a,b)); // b should not be zero
		break;
	default:
		printf("Wrong choice!");
	}
	return 0;
}

Program for Calculator in c using while loop

In this program, we will make a simple calculator using a while loop and an if-else statement instead of a switch case.

C program to create a Calculator using if-else

#include<stdio.h>
#include<stdlib.h>
int main()
{
int num1, num2, choice;
while(1)
    {
        printf("\n Menu Driven Program in c");
        printf("\n 1.Addition");
        printf("\n 2.Subtraction");
        printf("\n 3.Multiplication");    
        printf("\n 4.Division");
        printf("\n 5.exit");
        printf("\n Enter Choice:");
        scanf("%d",&choice);    
    if(choice>0 && choice<6)
    {
    if (choice==1)
        {
            printf("\n Enter 1st number: ");
            scanf("%d",&num1);
            printf("\n Enter 2nd number: ");
            scanf("%d",&num2);
            printf("\n %d + %d = %d",num1,num2,num1+num2);
        }
    if (choice==2)
        {
            printf("\n Enter 1st number: ");
            scanf("%d",&num1);
            printf("\n Enter 2nd number: ");
            scanf("%d",&num2);
            printf("\n %d - %d = %d",num1,num2,num1-num2);
        } 
    
    if (choice==3)
        {
            printf("\n Enter 1st number: ");
            scanf("%d",&num1);
            printf("\n Enter 2nd number: ");
            scanf("%d",&num2);
            printf("\n %d * %d = %d",num1,num2,num1*num2);
        } 
     
    
    if (choice==4)
        {
            printf("\n Enter 1st number: ");
            scanf("%d",&num1);
            printf("\n Enter 2nd number: ");
            scanf("%d",&num2);
            if(num2==2)
            printf("\n Denominator cannot be zero");
            else
            {
                printf("\n %d / %d = ",num1,num2);
                printf("%d",num1/num2);
            }
        }
    if(choice==5)
        exit(0);
    }            
    else printf("\n Wrong choice");
    }
    return 0;
}

Output for Menu-driven Calculator Program using while-loop and if-else

1. Addition
2. Subtraction
3. Multiplication
4. Division
5. exit
Enter Choice:1
Enter 1st number: 5
Enter 2nd number: 6
5 + 6 = 11

C Program to make Calculator using Switch Case

Durgesh Kumar gives this code. He was facing a problem with the same program. He was not able to run his last line of code. See in the comment section of this post.

When taking a character input, you must write scanf(" %c" &choice);. You have to give a space between " & %.

#include <stdio.h>

int main()
{
    int num1, num2, opt;
    char choice;
    // taking the input from the users
    printf("enter the first integer= ");
    scanf("%d", &num1);
    printf("enter the second integer= ");
    scanf("%d", &num2);

    printf("*****************************");
    do
    {

        printf("\n please enter your choice. \n\n 1.Addition\n 2.Subtraction \n 3.Multiplication \n 4.division \n 5.Modulas\n");
        scanf("%d", &opt);
        switch (opt)
        {
        case 1:
            printf("The addition of %d + %d = %d", num1, num2, num1 + num2);
            break;
        case 2:
            printf("the subtraction of %d - %d = %d", num1, num2, num1 - num2);
            break;
        case 3:
            printf("The multiplication of %d * %d = %d", num1, num2, num1 * num2);
            break;
        case 4:
            if (num2 == 0)
            {
                printf("this number can't divide by zero\n");
            }
            else
            {
                printf("the division of %d / %d = %d", num1, num2, num1 / num2);
            }
            break;
        case 5:
            if (num2 == 0)
            {
                printf("we can't find the remainder");
            }
            else
            {
                printf("the remainder of %d % %d = %d", num1, num2, num1 % num2);
            }
            break;
        default:
            printf("Please choose the correct option");
        }

        printf("\ndo you want to continue? press(y/n)");
        scanf(" %c", &choice);
    } while (choice == 'y');
    return 0;
}

About this calculator program in c using switch case:

In conclusion, we have just gone through the different calculator programs in c. It depends on your choice, but I recommend you make this program using a switch case. These types of programs are known as menu-driven programs.

2 comments

  1. good morning sir,

    this is Durgesh kumar. sir i have created a simple c program to make a calulator.
    but i have faced a problem and that is i am not able to run my last one code (do you continue? Press(y/n))
    here is my code
    // write a c program to make a sample calculater where operation will be choosed by users.

    #include
    #include

    int main()
    {
    int num1,num2,opt;
    char choice;
    // asking the input from the users
    printf("enter the first intgers= ");
    scanf("%d",&num1);
    printf("enter the second intgers= ");
    scanf("%d",&num2);

    printf("*****************************");
    do
    {

    printf("\n please enter your choice. \n\n 1.Addtion\n 2.Subtrcation \n 3.Multiplication \n 4.division \n 5.Modulas\n");
    scanf("%d",&opt);
    switch(opt)
    {
    case 1:
    printf("The addition of %d + %d = %d", num1,num2,num1+num2);
    break;
    case 2:
    printf("…
    1. Replace scanf("%c", &choice); with scanf(" %c", &choice);
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